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CBSE XII MATHEMATICS INTEGRATION IMPORTANT QUESTIONS

Integration Of Root Tanx Root Cotx Solve Integral 0 To Pi/4 + Dx

There are two methods to deal with π‘‘π‘Žπ‘›β‘π‘₯ (1) convert into 𝑠𝑖𝑛⁑π‘₯ and π‘π‘œπ‘ β‘π‘₯ , then solve using the properties of 𝑠𝑖𝑛⁑π‘₯ and π‘π‘œπ‘ β‘π‘₯. I = ∫ [tan x + c o t x] d x i = ∫ [tan x + 1 tan x] d x i = ∫ [tan x + 1 tan x] d x i = ∫ tan x (1 + c o t x) d x tan x = t 2, s e c 2 x d x = 2 t d t hence d x = 2 t d t 1 + t 4 a s (1 + tan 2 x = s e c 2 x) s.

$$\int\left( \sqrt{\tan x}+\sqrt{\cot x}\right)dx$$ stack exchange network stack exchange network consists of 178 q&a communities including stack overflow , the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. We take, (t + 1 t) = v β‡’ (1 βˆ’ 1 t2)dt = dv,&,t2 + 1 t2 = v2 βˆ’ 2. Integral from 0 to pi 2 root cot x root cot x root tan x dx.

Integration of root tan x + root cotX YouTube

Im gonna give u the solution and i hope it is the easiest, regardless of the fact that it could be a bit lengthy.
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I=∫ 0 2Ο€ ( tanx + cotx )dx i=∫ 0 2Ο€ ( cosxsinx + sinxcosx )dx i=∫ 0 2Ο€ ( sinxcosx sinx+cosx )dx letz=sinxβˆ’cosx,dz=(cosx+sinx)dx z 2=sin 2x+cos 2xβˆ’2sinxcosx z 2=1βˆ’2sinxcosx 2sinxcosx=1βˆ’z 2 sinxcosx= 21βˆ’z 2 when,x=0,t=βˆ’1;x= 2Ο€ ,t=1 i=∫ βˆ’11.

The answer is =2sqrt(tanx)+c we need tanx=sinx/cosx sinx=cosxtanx=tanx/secx therefore, the integral is i=int(sqrt(tanx)dx)/(sinxcosx)=int(sqrt(tanx)dx)/(tanx/secx*1/secx) =int(sec^2xdx)/sqrt(tanx) let u=tanx, =>, du=sec^2xdx the integral is i=int(du)sqrt(u) =sqrt(u)/(1/2) =2sqrt(u) =2sqrt(tanx)+c = 2 ∫ t 2 + 1 t 4 + 1 d t. ∴ i 1 = ∫ 1 u2 + (√2)2 du = 1 √2 arctan( u √2). Dx = 2tdt sec2x = 2tdt 1 + tan2x = 2tdt 1 + t4.

Integral of 0 to pi/2 root (cot x) / root( cotx)+root (tan x) dx get the answers you need, now!

Integral from 0 to Ο€/2 (√cot x) / [(√cot x + √tan x)] dx = login. Click hereπŸ‘†to get an answer to your question ️ int^ (√(tanx)+√(cotx))dx = I hope it works out for you… thank you. Ncert solutions for class 12 physics;

I = ∫ ( cot x + tan x) d x.

Ncert solutions for class 12. = ∫ ( tan x ( 1 + cot x)) d x. (2) change into sec2x, as derivative of tan x is sec2. L e t tan x = t 2.

T βˆ’ 1 t = u β‡’ (1 + 1 t2)dt = du,&,t2 + 1 t2 = u2 +2.

Ncert solutions for class 12 chemistry; T h e n, i = ∫ 0 Ο€ 4 ( sin. β‡’ d x = 2 t d t 1 + t 4. Hence, where, i 1 = ∫ 1 + 1 t2 t2 + 1 t2 dt.

∴ i = ∫ t ( 1 + 1 t 2) Γ— 2 t 1 + t 4 d t.

Sec 2 x d x = 2 t d t. Find integral of root tan x. L e t i = ∫ 0 Ο€ 4 ( tan.

indefinite integration of root tanx YouTube
indefinite integration of root tanx YouTube

Example 35 Find integral pi/6 to pi/3 1/ 1 + root(tan x
Example 35 Find integral pi/6 to pi/3 1/ 1 + root(tan x

Example 41 Evaluate integral [root cot x + root tan x] dx
Example 41 Evaluate integral [root cot x + root tan x] dx

What is ∫ (SQRT (tanx) +SQRT (cotx)) dx? Quora
What is ∫ (SQRT (tanx) +SQRT (cotx)) dx? Quora

Integration of root tan x + root cotX YouTube
Integration of root tan x + root cotX YouTube

Is there an easy method to integrate the root of tanx
Is there an easy method to integrate the root of tanx

Find the definite integral of sqrt(cotx) / [sqrt(cotx
Find the definite integral of sqrt(cotx) / [sqrt(cotx

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