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CBSE XII MATHEMATICS INTEGRATION IMPORTANT QUESTIONS

Integration Of Root Tanx Root Cotx Solve Integral 0 To Pi/4 + Dx

There are two methods to deal with π‘‘π‘Žπ‘›β‘π‘₯ (1) convert into 𝑠𝑖𝑛⁑π‘₯ and π‘π‘œπ‘ β‘π‘₯ , then solve using the properties of 𝑠𝑖𝑛⁑π‘₯ and π‘π‘œπ‘ β‘π‘₯. I = ∫ [tan x + c o t x] d x i = ∫ [tan x + 1 tan x] d x i = ∫ [tan x + 1 tan x] d x i = ∫ tan x (1 + c o t x) d x tan x = t 2, s e c 2 x d x = 2 t d t hence d x = 2 t d t 1 + t 4 a s (1 + tan 2 x = s e c 2 x) s.

$$\int\left( \sqrt{\tan x}+\sqrt{\cot x}\right)dx$$ stack exchange network stack exchange network consists of 178 q&a communities including stack overflow , the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. We take, (t + 1 t) = v β‡’ (1 βˆ’ 1 t2)dt = dv,&,t2 + 1 t2 = v2 βˆ’ 2. Integral from 0 to pi 2 root cot x root cot x root tan x dx.

Find the integral of sqrt(tanx) + sqrt(cotx). YouTube

Im gonna give u the solution and i hope it is the easiest, regardless of the fact that it could be a bit lengthy.
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I=∫ 0 2Ο€ ( tanx + cotx )dx i=∫ 0 2Ο€ ( cosxsinx + sinxcosx )dx i=∫ 0 2Ο€ ( sinxcosx sinx+cosx )dx letz=sinxβˆ’cosx,dz=(cosx+sinx)dx z 2=sin 2x+cos 2xβˆ’2sinxcosx z 2=1βˆ’2sinxcosx 2sinxcosx=1βˆ’z 2 sinxcosx= 21βˆ’z 2 when,x=0,t=βˆ’1;x= 2Ο€ ,t=1 i=∫ βˆ’11.

The answer is =2sqrt(tanx)+c we need tanx=sinx/cosx sinx=cosxtanx=tanx/secx therefore, the integral is i=int(sqrt(tanx)dx)/(sinxcosx)=int(sqrt(tanx)dx)/(tanx/secx*1/secx) =int(sec^2xdx)/sqrt(tanx) let u=tanx, =>, du=sec^2xdx the integral is i=int(du)sqrt(u) =sqrt(u)/(1/2) =2sqrt(u) =2sqrt(tanx)+c = 2 ∫ t 2 + 1 t 4 + 1 d t. ∴ i 1 = ∫ 1 u2 + (√2)2 du = 1 √2 arctan( u √2). Dx = 2tdt sec2x = 2tdt 1 + tan2x = 2tdt 1 + t4.

Integral of 0 to pi/2 root (cot x) / root( cotx)+root (tan x) dx get the answers you need, now!

Integral from 0 to Ο€/2 (√cot x) / [(√cot x + √tan x)] dx = login. Click hereπŸ‘†to get an answer to your question ️ int^ (√(tanx)+√(cotx))dx = I hope it works out for you… thank you. Ncert solutions for class 12 physics;

I = ∫ ( cot x + tan x) d x.

Ncert solutions for class 12. = ∫ ( tan x ( 1 + cot x)) d x. (2) change into sec2x, as derivative of tan x is sec2. L e t tan x = t 2.

T βˆ’ 1 t = u β‡’ (1 + 1 t2)dt = du,&,t2 + 1 t2 = u2 +2.

Ncert solutions for class 12 chemistry; T h e n, i = ∫ 0 Ο€ 4 ( sin. β‡’ d x = 2 t d t 1 + t 4. Hence, where, i 1 = ∫ 1 + 1 t2 t2 + 1 t2 dt.

∴ i = ∫ t ( 1 + 1 t 2) Γ— 2 t 1 + t 4 d t.

Sec 2 x d x = 2 t d t. Find integral of root tan x. L e t i = ∫ 0 Ο€ 4 ( tan.

Example 41 Evaluate integral [root cot x + root tan x
Example 41 Evaluate integral [root cot x + root tan x

Example 41 Evaluate integral [root cot x + root tan x] dx
Example 41 Evaluate integral [root cot x + root tan x] dx

Example 35 Find integral pi/6 to pi/3 1/ 1 + root(tan x
Example 35 Find integral pi/6 to pi/3 1/ 1 + root(tan x

solve integral 0 to pi/4 root tanx + root cotx dx
solve integral 0 to pi/4 root tanx + root cotx dx

Is there an easy method to integrate the root of tanx
Is there an easy method to integrate the root of tanx

Example 41 Evaluate integral [root cot x + root tan x] dx
Example 41 Evaluate integral [root cot x + root tan x] dx

Find the definite integral of sqrt(cotx) / [sqrt(cotx
Find the definite integral of sqrt(cotx) / [sqrt(cotx

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