We have multiple formulas for this. Integration of cosecx or cosec x. Click here👆to get an answer to your question ️ solve:
The integral `int sec^(2//3) \"x cosec\"^(4//3)\"x dx
6 rows we can prove that the integral of sec x to be ln | tan [ (x/2) + (π/4) ] | + c by using.
Ex 7.1, 19 sec 2 2 dx sec 2 2 = 1 cos 2 1 sin 2 = 1 cos 2 sin 2 1 = sin 2 cos 2 = tan 2 = sec 2 1 = sec 2
Where c is the integration constant. Integral of square cosecant $$\int \csc^{2}x \ dx$$ maybe some of them cause a bit of conflict the resolution of this integral, but we know very well that the integrals and the derivatives are linked by a very strong friendship bond, which means that if someone derives something and the result of that something is integrated, the result will be that something with. $\sec(x)=\dfrac{\frac d{dx}[\tan(x)+\sec(x)]}{\tan(x)+\sec(x)}$ now let $u=\tan(x)+\sec(x)$, you get $\sec(x)=\dfrac{du}u$, then you integrate both sides: A unique platform where students can interact with teachers/experts/students to get solutions to their queries.
I = (u2/2) + c.
5) log |sec 2x cosec 2x| + c. = ∫ sinx sinx +1. = ∫ sinx(sinx − 1) (sinx + 1)(sinx − 1) = ∫ sinx − sin2x cos2x dx. Or, ∫ cosec x = l o g | t a n x 2 | + c.
Then multiply through by x (x*secx) and integrate the x terms one by one to obtain an approximation to this integral.
Hendikeps2 and 62 more users found this answer helpful. This is also known as the antiderivative of cosecx. Sunanta meitei, meritnation expert added an answer, on 24/11/10. ∫ s e c 2 x + s e c x t a n x ( s e c x + t a n x).
2) log |secx + cosec x| + c.
Log a ^b = b log a log a b = b log a.therefore, − ln | cosec x + cot x | = ln 1/ | cosec x + cot x |. Now we will substitute u =. I = ∫ [ 1 / ( sec x + csc x ) ] dx.= ∫ { 1 / [ (1/cos x) + (1/sin x) ] } dx.= ∫ [ ( cos x + sin x ) / ( sin x · cos x ) ] dx.= 2 ∫ [ ( cos x + sin x ) / ( 2 sin x. Editor toolbars basic styles bold paragraph insert/remove numbered list insert/remove bulleted list insert image insert horizontal.
Answered apr 21, 2018 by rubby (52.4k points) selected apr 22, 2018 by vikash kumar.
(3) 1/2 log |sec 2x + tan 2x| + c Please log in or register to add a. 3) 1/2 log |sec 2x + tan 2x| + c. S e c x + t a n x s e c x + t a n x.
>> integration by substitution >> integrate cosecx dx | maths questions.
I = ( [log (secx+tanx)] 2/2) + c. To find the integral of sec x first we will multiply sec by. Students (upto class 10+2) preparing for all government exams, cbse board exam, icse board exam, state board exam, jee (mains+advance) and neet can ask questions from any subject and get quick answers by. Solve the problem in photo showing each step clearly.
Commented feb 9, 2019 by ayush bhatt (19 points) +1.
Hece we get the required equation as. = ∫ 1 1 + 1 sinx. 1) log |sec x + tan x| + c. ∫ 1 1 + cosecx.
4) log |sec 2x + cosec 2x| + c.
∫ s e c ( s e c x + t a n x) ( s e c x + t a n x).
