Subtract 2 x 2 x from both sides of the equation. Y = m x + b y = m x + b. Add 2 to both sides.
What is the equation of a line passing through A (2,3
When given the equation of a line in the form:
Divide each term by 3 3 and simplify.
With the new slope, use the slope intercept form and the point to calculate the intercept: Subtract 3y from both sides. Ax + by = c it is very easy to make a line that is perpendicular to the given line: Rewritten in slope intercept form, (2) becomes y = 3 2 x + 3.
Divide each term by 3 3 and simplify.
Xxxxxxy −6 = − 3 2 (x − 2) ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~. Perpendicular slopes must be opposite reciprocals of each other: Y = mx + b or 5 = 3 (1) + b, so b = 2. A line segment has endpoints j ( 2, 4 ) and l ( 6, 8 ).
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What is the slope of a line perpendicular to the line whose equation is 2x 3y 12? 2x −3y = 12 has a slope of m = 2 3. A) write the equation of a line perpendicular to l containing the point (3. Swap a and b change the sign of either a or b make the right side an arbitrary constant, k the two possible results are shown below:
Now, y intercept is b (put x=0).
All lines perpendicular to 2x − 3y = 12 have a slope of − 3 2. The slope of a perpendicular line is 3 2. (5,7) ( 5, 7) , 2x + 3y = 12 2 x + 3 y = 12. Since in the given equation the and terms are on the same side of the equals sign, take the opposite of the coefficent on and divide by the coefficient on to find the slope of the line.
Subtract 2 x 2 x from both sides of the equation.
So the slope of the line perpendicular to this line will be 3/2. Before you calculate the equation of the perpendicular line, you will need to find the slope of the line that crosses the two points. Find an equation of the line passing through the point (6,5) and perpendicular to the line whose equation is 2y+3x=6. Which is an equation of the line with slope 3 and passes through 2 1 )?
So the equation of the perpendicular line is of the form y = 3x /2 + b.
So y = 3 x + 2.
