Let the usual speed of the plane = x km/hr. Distance to the destination = 1500 km increased speed = 100 km/hr. Distance covered by the plane = 1500 km let the usual speed be s km/hr let the usual time taken be t hr.
An aeroplane left 50 minutes later than its scheduled time
A plane left 30 minutes late than the schedule time and in order to reach its destination 1500 km away in time,it has to increase its speed by 100 km/h from its usual speed.find its usual speed.
Hence, the original time must have been 2 hours and the original speed would be 750 kmph.
A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 km/h from the usual speed. We use the formula for determining time in terms of distance and speed which is, t = d s. So, according to the question. Find its usual speed a plane left 30 min later than the scheduled time and in order to reach the destination 1500km away in time it has to increase the speed by 250km/h from the usual speed.
Time take to reach the destination at the increased speed, t 2 = 1500 x + 100 h r.
Increased speed of the plane = ( x + 100) km/hr. A plane left 30 minutes later than the scheduled time and in order to reach its destination 1500 km away in time it has to increase its speed by 250. A plane left 30 minutes later then the scheduled time and in order to reach the destination 1500 km away in time, it has to increase the speed by 250 km/hr from the usual speed. , where t is the time, d is the distance and s is the speed of the plane.
A plane left 30 min later than the scheduled time and in order to reach its destination 1500 km away in time, it has to increase its speed by 250km/hr from its usual speed.
A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 km/h from the usual speed. It had to increase its speed by 100 km/h from the usual speed. Hence, the new speed would be. Then what is the usual speed of the aeroplane?
Closed nov 25, 2020 by ishti.
This is the solution of question from rd sharma book of class 10 chapter quadratic equations this question is also available in r s aggarwal book of class 10. A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 km/h from the usual speed. And in order to reach its destination 1500 km away in time, it has to increase its speed by 250 km/hour from its usual speed. Given distance d = 1500km and the speed increase by s= 250km/h also that the plane left 30 minutes later than the scheduled time.
Asked sep 27, 2018 in mathematics by minu (46.2k points) a plane left 30 minutes late than its scheduled time and in order to reach of destination 1500 km away in time.
Solution (by examveda team) by increasing the speed by 33.33%, it would be able to reduce the time taken for traveling by 25%. Time take to reach the destination at the usual speed, t 1 = 1500 x hr. It has to increase the speed by 250km/h from the usual seed. A plane left 30 minutes later than the scheduled time and in order to reach the destination 1500 km away in time, it had to increase the speed by 250 km/hr from the usual speed.
A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 k.
An aeroplane left 30 minutes later than its scheduled time; A plane left 30 minutes later than the scheduled time and in order to reach its destination 1500 km away on time, it has to increase its speed by 250 km/hr from its usual speed. Asked by anjana s | 23rd nov, 2014, 07:00: Find the usual speed of the plane.
A plane left 30 min later than the scheduled time and in order to reach the destination 1500km away in time it has to increase the speed by 250km/h from the usual speed.
A plane left 30 minutes later than the scheduled time and in order to reach the desination, 1500km away in time. An aeroplane left 30 mins later than its scheduled time and in order to reach its destination 1500km away in time, it has to increase its speed by 250 km/hr from its usual speed. But since this is able to overcome the time delay of 30 minutes, 30 minutes must be equivalent to 25% of the time originally taken. Let the usual speed of the plane = x km/hr.
Let the usual speed of the plane be x km/hr.
∴ speed in this instance = (s + 100) km/hr.
