This is the solution of question from rd sharma book of class 10 chapter quadratic equations this question is also available in r s aggarwal book of class 10. So, according to the question. A plane left 30 minutes late than the schedule time and in order to reach its destination 1500 km away in time,it has to increase its speed by 100 km/h from its usual speed.find its usual speed.
what is the equivalent resistance between A and B
∴ speed in this instance =.
A plane left 30 minutes later than the scheduled time and in order to reach the destination 1500 km away in time, it had to increase the speed by 250 km/hr from the usual speed.
Time take to reach the destination at the increased speed, t 2 = 1500 x + 100 h r. A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 km/h from the usual speed. Increased speed of the plane = ( x + 100) km/hr. Let the usual speed of the plane be x km/hr.
Asked sep 27, 2018 in mathematics by minu (46.2k points) a plane left 30 minutes late than its scheduled time and in order to reach of destination 1500 km away in time.
Let the usual speed of the plane be x km/hr. A plane left 30 minutes later than the scheduled time and in order to reach the desination, 1500km away in time. Speed increased by 100 km/hr. Solution (by examveda team) by increasing the speed by 33.33%, it would be able to reduce the time taken for traveling by 25%.
Hence, the original time must have been 2 hours and the original speed would be 750 kmph.
A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 km/h from the usual speed. A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 km/h from the usual speed. , where t is the time, d is the distance and s is the speed of the plane. And in order to reach its destination 1500 km away in time, it has to increase its speed by 250 km/hour from its usual speed.
Asked in aieee (12 years ago)
A plane left 30 minutes later than the scheduled time and in order to reach the destination 1500km away in time, it has to increase the speed by 250km/hr from the usual speed. An aeroplane left 30 minutes later than its scheduled time; ∴ speed in this instance = (s + 100) km/hr. While boarding an aeroplane, a passenger got hurt.
Distance covered by the plane = 1500 km.
It has to increase the speed by 250km/h from the usual seed. A plane left 30 minutes later than the scheduled time in order to reach its destination, 1500 km away it has to increase its speed by 250km/hr than his usual speed. The pilot showing promptness and concern, made arrangements to hospitalize the injured and so the plane started late by 30 minutes to reach the destination, 1500 km away in time, the pilot increased the speed by 100 km/hr. Let the usual speed of the plane = x km/hr.
The plane left 30 minutes late and reached on time.
Distance to the destination = 1500 km increased speed = 100 km/hr. A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase the speed by 250 km/h from the usual speed. The plane left 30 minutes late and reached on time. A plane left 30 minutes later than the schedule time and in order to reach its destination 1500 km away in time, it has to increase its speed by 250 km/hr from its usual speed.
Let the usual speed of the plane = x km/hr.
Time take to reach the destination at the usual speed, t 1 = 1500 x hr. It had to increase its speed by 100 km/h from the usual speed. A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 k. Hence, the new speed would be.
Let the usual time taken be t hr.
Find the original speed/hour of the plane. Distance covered by the plane = 1500 km let the usual speed be s km/hr let the usual time taken be t hr. Let the usual speed be s km/hr. But since this is able to overcome the time delay of 30 minutes, 30 minutes must be equivalent to 25% of the time originally taken.
