And in order to reach its destination 1500 km away in time, it has to increase its speed by 250 km/hour from its usual speed. Let time taken be y hr. , where t is the time, d is the distance and s is the speed of the plane.
Express 1.16bar as a rational number in the simplest form
It has to increase the speed by 250km/h from the usual seed.
Asked sep 27, 2018 in mathematics by minu (46.2k points) a plane left 30 minutes late than its scheduled time and in order to reach of destination 1500 km away in time.
Distance to the destination = 1500 km increased speed = 100 km/hr. So, according to the question. A plane left 30 minutes later than the scheduled time and in order to reach the destination 1500 km away in time, it had to increase the speed by 250 km/hr from the usual speed. Y = 1500 ÷ x.
Let the usual speed of the plane = x km/hr.
A plane left half an hour later than the scheduled time and in order to reach its destination 1500 kilometers away in time, it had to increase its speed by 33.33 percent over its usual speed. A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 km/h from the usual speed. 30 minutes = 0.5 hours. A plane left 30 minutes later than the schedule time and in order to reach its destination 1500 km away in time, it has to increase its speed by 250 km/hr from its usual speed.
A plane left 30 minutes late than the schedule time and in order to reach its destination 1500 km away in time,it has to increase its speed by 100 km/h from its usual speed.find its usual speed.
Given distance d = 1500km and the speed increase by s= 250km/h also that the plane left 30 minutes later than the scheduled time. A) 250 kmph b) 500 kmph c) 750 kmph d) 1000 kmph e) 1200 kmph The plane left 30 minutes late and reached on time. A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 k.
∴ speed in this instance = (s + 100) km/hr.
Distance covered by the plane = 1500 km let the usual speed be s km/hr let the usual time taken be t hr. A plane left 30 minutes later then the scheduled time and in order to reach the destination 1500 km away in time, it has to increase the speed by 250 km/hr from the usual speed. An aeroplane left 30 minutes later than its scheduled time; Let the usual speed of the plane be x km/hr.
This is the solution of question from rd sharma book of class 10 chapter quadratic equations this question is also available in r s aggarwal book of class 10.
The plane left 30 minutes late and reached on time. A plane left 30 minutes later than the scheduled time and in order to reach the desination, 1500km away in time. A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 km/h from the usual speed. A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase the speed by 250 km/h from the usual speed.
According to the question, plane left 30min later than the scheduled time.
A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 km/h from the usual speed. Distance covered by the plane = 1500 km let the usual speed be s km/hr let the usual time taken be t hr. ∴ speed in this instance = (s + 100) km/hr. Time taken by the aeroplane =x− 21.
It had to increase its speed by 100 km/h from the usual speed.
X = 1500 ÷ y.
