A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase the speed by 250 km/h from the usual speed. Let the usual speed of the plane be x km/hr. A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 km/h from the usual speed.
A plane left 30 minutes later than the schedule time and in order to reach its destination 1500 km away in time, it has to increase its speed by 250.
Asked nov 3, 2017 in class x maths by akansha expert (7.8k points) a plane left 30 minutes later than the scheduled time and in order to.
A plane left 30 min later than the scheduled time and in order to reach its destination 1500 km away in time, it has to increase its speed by 250km/hr from its usual speed. A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 km/h from the usual speed. Solution (by examveda team) by increasing the speed by 33.33%, it would be able to reduce the time taken for traveling by 25%. Let the usual speed of the plane = x km/hr.
Hence, the new speed would be.
A plane left 30 minutes later than the scheduled time and in order to reach the desination, 1500km away in time. 30 minutes = 0.5 hours. An aeroplane left 5 0 minutes later than its scheduled time, and in order to reach the destination, 1 2 5 0 k m away, in time, it had to increase its speed by 2 5 0 k m / h r from its usual speed. Time take to reach the destination at the usual speed, t 1 = 1500 x hr.
A plane left 30 minutes late than the schedule time and in order to reach its destination 1500 km away in time,it has to increase its speed by 100 km/h from its usual speed.find its usual speed.
Distance covered by the plane = 1500 km let the usual speed be s km/hr let the usual time taken be t hr. Distance covered by the plane = 1500 km let the usual speed be s km/hr let the usual time taken be t hr. ∴ speed in this instance = (s + 100) km/hr. A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 k.
But since this is able to overcome the time delay of 30 minutes, 30 minutes must be equivalent to 25% of the time originally taken.
The plane left 30 minutes late and reached on time. So, according to the question. A plane left 30 min later than the scheduled time and in order to reach the destination 1500km away in time it has to increase the speed by 250km/h from the usual speed. A plane left 30 minutes later than the scheduled time and in order to reach its destination 1500km away in time it has to increase its speed by 250 km/hr from its usual speed.
Let the usual speed of the plane = x km/hr.
Let time taken be y hr. A plane left 30 minutes later than the scheduled time and in order to reach the destination 1500 km away in time, asked oct 1, 2020 in linear equations by chandan01 ( 51.3k points) pair of linear equations in two variables It had to increase its speed by 100 km/h from the usual speed. K m / h r
Asked in aieee (12 years ago)
Hence, the original time must have been 2 hours and the original speed would be 750 kmph. Time take to reach the destination at the increased speed, t 2 = 1500 x + 100 h r. A plane left 30 minutes later than the scheduled time and in order to reach the destination 1500 km away in time, it had to increase the speed by 250. ∴ speed in this instance = (s + 100) km/hr.
Distance to the destination = 1500 km increased speed = 100 km/hr.
A plane left 30 minutes late than its scheduled time and in order to reach the destination $1500\ km$ away in time, it had to increase its speed by $100\. It has to increase the speed by 250km/h from the usual seed. Y = 1500 ÷ x. X = 1500 ÷ y.
Increased speed of the plane = ( x + 100) km/hr.
Asked sep 27, 2018 in mathematics by minu (46.2k points) a plane left 30 minutes late than its scheduled time and in order to reach of destination 1500 km away in time.
