Time take to reach the destination at the increased speed, t 2 = 1500 x + 100 h r. A plane left 30 minutes late than its scheduled time and in order to reach the destination $1500\ km$ away in time, it had to increase its speed by $100\. Late = 30 min distance = 1500 km speed increase = 100 km / hr to find:
When a current carrying conductor is placed in a
Asked nov 3, 2017 in class x maths by akansha expert (7.8k points)
A plane left 30 min later than the scheduled time and in order to reach its destination 1500 km away in time, it has to increase its speed by 250km/hr from its usual speed.
Pair of linear equations in two variables. Asked sep 27, 2018 in mathematics by minu (46.2k points) a plane left 30 minutes late than its scheduled time and in order to reach of destination 1500 km away in time. A plane left 30 minutes later than the scheduled time and in order to reach the desination, 1500km away in time. Increased speed of the plane = ( x + 100) km/hr.
It had to increase its speed by 100 km/h from the usual speed.
Find the rate at which i was walking. Let the usual speed be s km/hr. A plane left 30 minutes later than the scheduled time and in order to reach the destination 1500 km away in time, it had to increase the speed by 250 km/hr from the usual speed. Let the usual speed of the plane = x km/hr.
A plane left 30 min late due to bad weather, but in order to reach its destination 1500 km away on time it has to increase its speed by 250 km/hr.
Speed is increased by 33.33% = (750*33.33)/100 = 250kmph. Time take to reach the destination at the usual speed, t 1 = 1500 x hr. Let the usual speed of the plane be x km/hr. Let the usual time taken be t hr.
Let the usual time taken by the aeroplane =xkm/hr.
Time taken to cover 1500 km with usual speed, t 1 =. A plane left 30 minutes late than the schedule time and in order to reach its destination 1500 km away in time,it has to increase its speed by 100 km/h from its usual speed.find its usual speed. We know that, speed = time distance. Distance to the destination = 1500 km increased speed = 100 km/hr.
Original speed of a plane is =750kmph.
A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 km/h from the usual speed. A plane left 30 minutes late than its scheduled time and in order to reach the destination1500 km away in time, it had to increase the speed by 100 km/h from the. If i had walked 1 km/hr faster, i would have taken 15 minutes less to walk 3 km. A plane left 30 minutes later than the scheduled time and in order to reach its destination 1500 km away in time, it has to increase its speed by 250 km/hr from its usual speed.
Let the usual speed of the plane = x km/hr.
The plane left 30 minutes late and reached on time. Hence, the total time taken to cover 1500kms is 2 hours. For 30 mins delay it would be equal to 25%. Distance to the destination =1500km.
So, according to the question
Distance covered by the plane = 1500 km. A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 km/h from the usual speed. A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 km/h from the usual speed. The angry arjun carried some arrows for fighting.
Distance covered by the plane = 1500 km let the usual speed be s km/hr let the usual time taken be t hr.
It has to increase the speed by 250km/h from the usual seed. According to the question, plane left 30min later than the scheduled time. ∴ speed in this instance = (s + 100) km/hr. Now the new speed of the plane is = 750+250.
The plane left 30 minutes late and reached on time.
Let the usual speed of the plane be x km/hr A plane left 30 min later than the scheduled time and in order to reach the destination 1500km away in time it has to increase the speed by 250km/h from the usual speed. A unique platform where students can interact with teachers/experts/students to get solutions to their queries. ∴ speed in this instance = (s + 100) km/hr.
This is the solution of question from rd sharma book of class 10 chapter quadratic equations this question is also available in r s aggarwal book of class 10.
